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Tangents are drawn to the  circle \mathrm{x^2+y^2=50} from a point ‘P’ lying on the x-axis. These tangents meet the  y-axis at points\mathrm{ 'P_{1}'} and \mathrm{ \text { 'P2' }}.  Possible coordinate of  ‘P’  so that area  of  triangle \mathrm{ \mathrm{PP} _{1}\mathrm{P} _{2}} is  minimum, is

 

Option: 1

 (12,  0)


 


Option: 2

(10, 0)

 


Option: 3

(-10, 0)


Option: 4

(-10, 0)


Answers (1)

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\mathrm{\begin{aligned} & O P=5 \sqrt{2} \sec \theta \\ & O P_1=5 \sqrt{2} \operatorname{cosec} \theta \\ & \qquad P_1 P_2=\frac{100}{\sin 2 \theta} \\ & \left(\Delta \mid P P_1 P_2\right)_{\text {min }}=100 \Rightarrow \theta=\pi / 4 \\ & \Rightarrow O P=10 \Rightarrow P=(10,0),(-10,0) . \end{aligned}}

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