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  • Tell me? - Complex numbers and quadratic equations - JEE Main-8

Let f\left ( x \right )= x^{2}+2\left ( a-1 \right )x+\left ( a^{2}+1 \right ) then the values of 'a' for which f\left ( x \right )= 0 has real and equal roots is

  • Option 1)

    a=0

  • Option 2)

    a=1

  • Option 3)

    a=2

  • Option 4)

    a=3

 

Answers (1)

best_answer

\\*For\; \; x^{2}+2(a-1)x+(a^{2}+1)=0,  to have real and equal roots , D=0

\\*\Rightarrow 4(a^{2}-2a+1)-4(a^{2}+1)=0\\*\Rightarrow a=0

 

Quadratic Expression Graph when a > 0 & D = 0 -

Real and Equal roots of

f\left ( x \right )= ax^{2}+bx+c

& D= b^{2}-4ac

- wherein

 

 

 


Option 1)

a=0

This is correct

Option 2)

a=1

This is incorrect

Option 3)

a=2

This is incorrect

Option 4)

a=3

This is incorrect

Posted by

Himanshu

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