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A projectile is fired at an angle \theta with initial elocity v, has a maximum height H. If initial velocity be tripled at the same angle of projection then its maximum height becomes

  • Option 1)

    \frac{H}3

  • Option 2)

    3H

  • Option 3)

    \frac{H}9

  • Option 4)

    9H

 

Answers (1)

best_answer

Let the maximum height be H.

H = \frac{v^{2}sin^{2}(\theta)}{2g}

intial velocity v is tripled 

so maximum height would become 9 times means 9H would be the right answer

Posted by

Vishwash Tetarwal

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