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  • The amplitude of the magnetic field of a harmonic electromagnetic wave in vacuum is <img alt="\mathrm{\mathrm{B}_0=510 \mathrm{nT}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7

The amplitude of the magnetic field of a harmonic electromagnetic wave in vacuum is \mathrm{\mathrm{B}_0=510 \mathrm{nT}}. The amplitude of the electric field part of the wave is:
 

Option: 1

\mathrm{120 \mathrm{NC}^{-1}}

 


Option: 2

\mathrm{134 \mathrm{NC}^{-1}}
 


Option: 3

\mathrm{510 \mathrm{NC}^{-1}}
 


Option: 4

\mathrm{153 \mathrm{NC}^{-1}}


Answers (1)

best_answer

Here, \mathrm{\mathrm{B}_0=510 \mathrm{nT}=510 \times 10^{-9} \mathrm{~T}}

\mathrm{ \mathrm{E}_0=\mathrm{cB}_0=3 \times 10^8 \times 510 \times 10^{-9}=153 \mathrm{NC}^{-1} }

Hence option 4 is correct.
 

Posted by

himanshu.meshram

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