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  •  The area of the region enclosed by the curve  and its tangent at the point (-1,-1) is <div cla

 The area of the region enclosed by the curve y=x^3 and its tangent at the point (-1,-1) is 

Option: 1

\frac{23}{4}


Option: 2

\frac{19}{4}


Option: 3

\frac{31}{4}


Option: 4

\frac{27}{4}


Answers (1)

best_answer

\text{equation of tangent } : y+1=3(x+1)\\ i.e. y=3 x+2\\ \text{ Point of intersection with curve } (2,8)\\ \text {So Area } =\int_{-1}^2\left((3 \mathrm{x}+2)-\mathrm{x}^3\right) \mathrm{dx}=\frac{27}{4}

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Riya

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