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  • The area of the triangle formed by joining the origin to the points of intersection of the line <img alt="\mathrm{\sqrt{5} x+2 y=3 \sqrt{5}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5

The area of the triangle formed by joining the origin to the points of intersection of the line \mathrm{\sqrt{5} x+2 y=3 \sqrt{5}} and circle \mathrm{x^2+y^2=10} is

 

Option: 1

6


Option: 2

5


Option: 3

4


Option: 4

3


Answers (1)

best_answer

Length of the perpendicular on the given line from origin \mathrm{' p ' =\sqrt{5}}

Length of the chord \mathrm{=2 \sqrt{r^2-p^2}=2 \sqrt{5}}

So, the area of the triangle \mathrm{=\frac{1}{2} \times base \times height}

\mathrm{ =\frac{1}{2} \times 2 \sqrt{5} \times \sqrt{5}=5 }

Hence option 2 is correct.


 

Posted by

vishal kumar

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