The atomic number of Unnilunium is ________.
Let's break the IUPAC Name-
Unnilunium = Un + nil + Un + ium
Un = 1
nil = 0
un = 1
So, The atomic number will be 101.
Ans = 101
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50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pKb of ammonia solution is 4.75, the pH of the mixture will be : Option: 1 3.75 Option: 2 4.75
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