Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The average speed of gas molecules in a gas present in equilibrium mixture is:Option: 1 <img alt="\propto T" src="https://learn.careers360.com/latex-

The average speed of gas molecules in a gas present in equilibrium mixture is:

Option: 1

\propto T


Option: 2

\propto T^\frac{1}{2}


Option: 3

\propto T^2


Option: 4

Nothing can be said.


Answers (1)

best_answer

We know, Average \: speed \: of\: the\: gas\: molecules(u_{av})=\sqrt{\frac{2RT}{M}}

Thus it is clear that u_{av} \propto T^\frac{1}{2}

Therefore, Option(2) is correct

Posted by

qnaprep

View full answer

Similar Questions

Trending Articles/News

anam-khan

AP EAMCET second phase results 2025 for agriculture, pharmacy on June 25
anam-khan

AP EAMCET Counselling 2025: Cut-offs for agricultural engineering, BTech ECE closing ranks
anam-khan

AP EAMCET cut-offs 2025 for BTech civil, chemical engineering in top colleges; counselling soon

Latest Question