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  • The average velocity of an ideal gas molecule at is 0.3 m/s. The aver

The average velocity of an ideal gas molecule at 27^{\circ} \mathrm{C} is 0.3 m/s. The average at 927^{\circ} \mathrm{C} will be -

Option: 1

\mathrm{0.6 \mathrm{~m} / \mathrm{s}}


Option: 2

0.3 \mathrm{~m} / \mathrm{s}


Option: 3

0.9 \mathrm{~m} / \mathrm{s}


Option: 4

3.0 \mathrm{~m} / \mathrm{s}


Answers (1)

best_answer

Expression for a verage vlocity is \mathrm{\mu_{a v}=\sqrt{\frac{8 R T}{\pi M}}}

 

for the same gas but at different temperabore,
\mathrm{ \frac{\operatorname{Uavg}\left(T_1\right)}{\operatorname{Uavg}\left(T_2\right.)}=\sqrt{\frac{T_1}{T_2}}=\sqrt{\frac{300}{1200}}=\frac{1}{2} }


\mathrm{ \Rightarrow \mu_{a v}\left(927^{\circ} \mathrm{c}\right)=2 \times \mu_{a v}\left(2 7^{\circ} \mathrm{c}\right) = 0.6 \mathrm{~m} / \mathrm{s} }

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Riya

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