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The bond order is maximum in

Option: 1

O_{2}
 


Option: 2

O_{2}^{-1}


Option: 3

O_{2}^{+1}

 


Option: 4

O_{2}^{-2}


Answers (1)

best_answer

First, find the value of bond order (Counting only p orbital electrons)-

\mathrm{O_2}\textup{, bond order = }\frac{6-2}{2}=2

\mathrm{O_2^{-1}}\textup{, bond order = }\frac{6-3}{2}=1.5

\mathrm{O_2^{+1}}\textup{, bond order = }\frac{6-1}{2}=2.5

\mathrm{O_2^{-2}}\textup{, bond order = }\frac{6-4}{2}=1

So, The bond order is maximum in \mathrm{O_{2}^{+1}}.

Hence, the correct answer is Option (3).

Posted by

Riya

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