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  • The cathode of a photoelectric cell is changed such that the work function changes from <img alt="\mathrm{\mathrm{W}_1 to \mathrm{W}_2\left(\mathrm{~W}_2>\mathrm{W}_1\right)}" src="https://entra

The cathode of a photoelectric cell is changed such that the work function changes from \mathrm{\mathrm{W}_1 to \mathrm{W}_2\left(\mathrm{~W}_2>\mathrm{W}_1\right)}. If the currents before and after change are \mathrm{\mathrm{I}_1 \: and \: \mathrm{I}_2}, all other conditions unchanged, then (assuming \mathrm{\mathrm{hv}>\mathrm{W}_2} )
 

Option: 1

\mathrm{I}_1=\mathrm{I}_2
 


Option: 2

\mathrm{I}_1<\mathrm{I}_2

 


Option: 3

\mathrm{I}_1>\mathrm{I}_2
 


Option: 4

\mathrm{I}_1<\mathrm{I}_2<2 \mathrm{I}_1


Answers (1)

best_answer

As along as \mathrm{hv >\mathrm{W}}, the work function has no effect on the current. So, work function does not play any role here. Further, the photo-electric currentis proportional to intensity of light. Here, there is no change in the intensity of light. Hence \mathrm{I_1=I_2}.

 

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manish

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