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The chance of a student passing an exam is 20 % The chance of a student passing the exam and gelting above 90 % in it is 5%. GIVEN that a student passes the examination, the probability that the student gets above 90% marks is

Option: 1

\frac{1}{18}


Option: 2

\frac{1}{4}


Option: 3

\frac{2}{9}


Option: 4

\frac{5}{18}


Answers (1)

best_answer

Let
A : Sludent getting above 90 % Marks
B : Student passes exam.

\therefore \quad P(A \cap B)=\frac{P(A \cap B)}{P(B)}

        =\frac{\begin{array}{c} P(\text { student passes \& } \\ \text { getting above } 90 \%) \end{array}}{P(\text { student passes exam })}

        =\frac{0.05}{0.2}=\frac{1}{4}

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Ritika Kankaria

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