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The chords of contact of the pair of tangents drawn from a point on the line \mathrm{3 x+y=4} to the circle \mathrm{x}^{2}+\mathrm{y}^{2}=1 pass through a fixed point

Option: 1

(2,4)


Option: 2

\left(-\frac{1}{2},-\frac{1}{4}\right)


Option: 3

\left(\frac{1}{2}, \frac{1}{4}\right)


Option: 4

(-2,-4)


Answers (1)

best_answer

The chord of contact of tangents from (\alpha, \beta) is

\alpha x+\beta y=1
Hence, (a) passes through \left(\frac{1}{2}, \frac{1}{4}\right)

Hence (c) is correct answer.

Posted by

Anam Khan

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