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The chords of contact of the pair of tangents drawn from each point on the line \mathrm{2 x+y=4} to the circle

\mathrm{x^2+y^2=1}  pass through a fixed point-

Option: 1

(2,4)


Option: 2

\mathrm{\left(-\frac{1}{2},-\frac{1}{4}\right)}


Option: 3

\mathrm{\left(\frac{1}{2}, \frac{1}{4}\right)}


Option: 4

(-2,-4)


Answers (1)

best_answer

The chord of contact of tangents from \mathrm{(\alpha, \beta)} is

\mathrm{\alpha x+\beta y=1}                                          ......(1)

Hence, (1) passes through \mathrm{\left(\frac{1}{2}, \frac{1}{4}\right)}.

Hence (c) is correct answer.

Posted by

seema garhwal

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