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The circle \mathrm{x^2+y^2+2 \lambda y=0}, \mathrm{\lambda \in R}, touches the parabola \mathrm{x^2=4 y} externally. Then
 

Option: 1

\lambda>0
 


Option: 2

\lambda<0
 


Option: 3

\lambda=0
 


Option: 4

None of these


Answers (1)

best_answer
\mathrm{ x^2+y^2+2 \lambda y=0, \lambda \in R }
centre \mathrm{ (0,-\lambda) }
Circle will touch parabola externally only for \mathrm{ \lambda>0 }

Hence option 1 is correct.

Posted by

Pankaj Sanodiya

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