Get Answers to all your Questions

header-bg qa

The coefficient of t24 in (1 + t2)12 (1 + t12) (1 + t24) is:

Option: 1

12C6 + 3


Option: 2

12C6 + 1


Option: 3

12C6 


Option: 4

12C6 + 2


Answers (1)

best_answer

(1 + t2)12 (1 + t12) (1 + t24)

Coefficient of t24

= 1 × coefficient of t24 in (1 + t2)12 + 1 × coefficient of t12 in (1 + t2)12 + 1 × constant term in (1 + t2)12

= 12C12 + 12C6 + 12C0 = 1 + 12C6 + 1 = 12C6 + 2

Posted by

Rishi

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE