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The coordinates of a point on the line \mathrm{x-y=5} such that the point is at equal distances from the lines \mathrm{|x|=-|y|} are

Option: 1

(-5,0)


Option: 2

(0,0)


Option: 3

(0,5)


Option: 4

(0,-5)


Answers (1)

best_answer

\mathrm{|x|=-|y| \Rightarrow x-y=0 \; and \: x+y=0}

Bisectors of the angles between these are \mathrm{\frac{x-y}{\sqrt{2}}= \pm \frac{x+y}{\sqrt{2}}}

\mathrm{\Rightarrow y=0\; and \; x=0}
By solving \mathrm{y=0, x-y=5} we get one of the required points while by solving \mathrm{x=0, x-y=5} we get the other point.

Posted by

Irshad Anwar

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