Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The coordinates of the point on the parabola , which is nearest to the s

The coordinates of the point on the parabola y=x^2+7 x+2, which is nearest to the straight line y=3 x-3 are ......

Option: 1

(-2,4)
 


Option: 2

(3,5)
 


Option: 3

(-2,-8)
 


Option: 4

(0,1)


Answers (1)

best_answer

Any point on the parabola is \left(x, x^2+7 x+2\right)

Its distance from the line y=3 x-3 is given by 

            \begin{aligned} P & =\left|\frac{3 x-\left(x^2+7 x+2\right)-3}{\sqrt{(9+1)}}\right|=\left|\frac{x^2+4 x+5}{\sqrt{10}}\right| \\ \\& =\frac{x^2+4 x+5}{\sqrt{10}}\left(\text { as } x^2+4 x+5>0, \text { for all } x \in R\right) \end{aligned}

   \begin{array}{ll} \therefore & \frac{d P}{d x}=0 \\ \\\Rightarrow & x=-2 \end{array}

\therefore The required point \equiv(-2,-8)

Posted by

rishi.raj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 final answer key likely in February 2nd week; result date, marking scheme
anam-khan

JEE Mains 2025 Answer key (OUT) LIVE: Session 1 result by February 12 on jeemain.nta.nic.in; cut-off
anam-khan

JEE Main Marks vs Percentile 2025: How many marks do you need to score 95+ percentile?

Latest Question