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  • The correct order of bond dissociation energy among , is shown i

The correct order of bond dissociation energy among , N_{2},O_{2},O_{2}^{-} is shown in which of the following arrangements ?

Option: 1

N_{2}>O_{2}^{-}>O_{2},


Option: 2

O_{2}^{-}>O_{2}>N_{2}


Option: 3

N_{2}>O_{2}>O_{2}^{-}


Option: 4

O_{2}>O_{2}^{-}>N_{2}


Answers (1)

best_answer

The higher is the bond order, more is the dissociation energy. Lets check Bond Orders for each of the given species

N_2 : 3; \quad O_2 : 2; \quad O_2^- : 1.5

\therefore Order of Bond dissociation energy is N_{2}> O_{2}> O_{2}^{-}

Therefore, option (3) is correct.

Posted by

himanshu.meshram

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