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  • The correct order of increasing ionic radii isOption: 1 <img alt="\mathrm{Mg}^{2+}<\mathrm{Na}^{+}<\mathrm{F}^{-}<\mathrm{O}^{2-}<\mathrm

The correct order of increasing ionic radii is

Option: 1

\mathrm{Mg}^{2+}<\mathrm{Na}^{+}<\mathrm{F}^{-}<\mathrm{O}^{2-}<\mathrm{N}^{3-}


Option: 2

\mathrm{N}^{3-}<\mathrm{O}^{2-}<\mathrm{F}^{-}<\mathrm{Na}^{+}<\mathrm{Mg}^{2+}


Option: 3

\mathrm{F}^{-}<\mathrm{Na}^{+}<\mathrm{O}^{2-}<\mathrm{Mg}^{2+}<\mathrm{N}^{3-}


Option: 4

\mathrm{Na}^{+}<\mathrm{F}^{-}<\mathrm{Mg}^{2+}<\mathrm{O}^{2-}<\mathrm{N}^{3-}


Answers (1)

In isoelectronic species, the ionic radii decreases with the increase in positive change on the ion

Thus, the order of ionic radii is

\mathrm{Mg}^{2+}<\mathrm{Na}^{+}<\mathrm{F}^{-}<\mathrm{O}^{2-} < \mathrm{N}^{3-}

Hence, answer is Option (1)

Posted by

Sumit Saini

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