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  • The current flowing through resistor in the circuit shown in the figure is: <img alt="" src="https:

The current flowing through 10\Omega resistor in the circuit shown in the figure is:

Option: 1

50 mA


Option: 2

20 mA


Option: 3

40 mA


Option: 4

80 mA


Answers (1)

best_answer

In the given circuit, junction diode D_{1} is forward biased and will conduct whereas junction diode  D_{2}  is reverse biased and will not conduct. Therefore current through 10\Omega resistor is

\mathrm{\mathrm{I}=\frac{2 \mathrm{~V}}{10 \Omega+15 \Omega}=0.08 \mathrm{~A}=80 \mathrm{~mA}}

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Anam Khan

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