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  • The current gain of a transistor in a common emitter configuration is 40. If the emitter current is 8.2 mA, then base current isOption: 1 0.02 mA

The current gain of a transistor in a common emitter configuration is 40. If the emitter current is 8.2 mA, then base current is

Option: 1

0.02 mA


Option: 2

0.2 mA


Option: 3

2.0 mA


Option: 4

0.4 mA


Answers (1)

best_answer

\mathrm{\begin{aligned} & \beta=\frac{I_c}{I_b}=\frac{I_e-I_b}{I_b}=\frac{I_e}{I_b}-1 \text { or } \frac{I_e}{I_b}=1+\beta \\ & \text { or } I_b=\frac{I_e}{1+\beta}=\frac{8.2}{1+40}=\frac{8.2}{41}=0.20 \mathrm{~mA} . \end{aligned} }

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Irshad Anwar

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