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The current gain of a transistor in common – emitter mode is 49. The change in collector current and emitter current corresponding to the change in base current by \mathrm{5.0\; \mu\: A } will be:

Option: 1

245 \mu \mathrm{A}, \; 250 \mu \mathrm{A}


Option: 2

\quad 240 \mu \mathrm{A}, 235 \mu \mathrm{A}


Option: 3

260 \mu \mathrm{A}, 255 \mu \mathrm{A}


Option: 4

none of these


Answers (1)

best_answer

\mathrm{Here, \beta=49, \Delta \mathrm{l}_{\mathrm{B}}=5.0 \mu \mathrm{A}

\mathrm{\therefore \quad \Delta \mathrm{I}_{\mathrm{C}}=\beta \Delta \mathrm{I}_{\mathrm{B}}=49 \times 5.0 \mu \mathrm{A}=245 \mu \mathrm{A}}

\mathrm{\Delta \mathrm{I}_{\mathrm{E}}=\Delta \mathrm{I}_{\mathrm{B}}+\Delta \mathrm{I}_{\mathrm{C}}=5.0 \mu \mathrm{A}+245 \mu \mathrm{A}=250 \mu \mathrm{A}}

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Ritika Jonwal

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