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  • The current in the ammeter for the given network of resistors connected to the battery of emf 10 V is equal to <img alt="" src="https://cdn.entrance360.com/media/uploads/2023/07/10/12.PNG

The current in the ammeter for the given network of resistors connected to the battery of emf 10 V is equal to

 

Option: 1

1.25 A


Option: 2

2.25 A
 


Option: 3

2.5 A 


Option: 4

none of these


Answers (1)

best_answer

Since the equivalent resistance between P & Q is equal to 2\; \Omega

\therefore \because i=\frac{10}{2}=5 \: amp

Since the current through the ammeter is equal to i/4

i_{A} = i/4 = 5/4 = 1.25 \; amp.

Posted by

avinash.dongre

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