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The current in wire \mathrm{AF} in the figure given below:


 

Option: 1

10 \mathrm{~A}


Option: 2

15 \mathrm{~A}


Option: 3

5 \mathrm{~A}


Option: 4

12 \mathrm{~A}


Answers (1)

best_answer

Current dustribution is given in the figure below:


Applying \mathrm{KVL} in the loop ABEFA:

\mathrm{i_{1}+30+2\left(i_{1}+i_{2}\right)-10=0}
\mathrm{\Rightarrow 3 i_{1}+2 i_{2}+20=0 \: -(1)}

Applying kirchoff voltage law in BCDEB

\mathrm{30+2\left(i_{1}+i_{2}\right)+50+2 i_{2}=0}
\mathrm{\Rightarrow 2 i_{2}+i_{1}+40=0-2\, -(2)}

solving (1) & (2)

\mathrm{3\left[-40-2 i_{2}\right]+2 i_{2}+20 =0}
\mathrm{\Rightarrow-120-4 i_{2}+20=0\: \Rightarrow i_{2}=-25 \mathrm{~A} }.
                                                     \mathrm{\Rightarrow i_{1}=10 \mathrm{~A}}.
                                           

Posted by

sudhir.kumar

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