Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

The current passing through $2\, \Omega$ resistance is:

Option: 1
$\frac{4}{3} \mathrm{~A}$

Option: 2
$\frac{5}{3} \mathrm{~A}$

Option: 3
$2 \mathrm{~A}$

Option: 4
$\frac{8}{3} \mathrm{~A}$

Answers (1)

best_answer

We can replace the right part of the circuit with an equivalent resistance of $2 \, \Omega$ .

$2 \, \Omega$ and $1 \, \Omega$ in series $= 3 \, \Omega$ .
$3 \, \Omega$ and $6\, \Omega$ in
$\text { parallel }=\frac{6 \times 3}{9}=2 \Omega$
$2\, \Omega$ and $4\, \Omega$ in series $= 6\, \Omega$
$6\, \Omega$ and $3\, \Omega$ in parallel $= 2\, \Omega$

$\mathrm{R_{\text {eq }}=4+4+2=10\, \Omega}$
$\mathrm{ i=\frac{120}{10}=12 \mathrm{~A}}$ .

$\mathrm{ \Rightarrow}$ current through
$\mathrm{2 \, \Omega}$ is $\mathrm{\frac{8}{3}\, A}$ .

Posted by

Suraj Bhandari

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

5 g of Na₂SO₄ was dissolved in x g of H₂O. The change in freezing point was found to be 3.82⁰C. If Na₂SO₄ is 81.5% ionised, the value of x (K

A capacitor is made of two square plates each of side 'a' making a very small angle $\alpha$

A solution of m-chloroaniline, m-chlorophenol and m-chlorobenzoic acid in ethyl acetate was extracted initially with a saturated solution of NaHCO₃ to give fraction A. The leftover organic phase was extracted with d

Latest Question