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The current voltage relation of diode ise relation of diode is given by I = (e^1000V/T -1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring V while measuring the current of 5 mA at 300 K,what will be the error in the value of current in mA ?
Option: 1
0.2 mA

Option: 2
0.02 mA

Option: 3
0.5 mA

Option: 4
0.05 mA

Answers (1)

best_answer

Given $5 mA=\left ( e^{\frac{1000V}{T}}-1 \right )$

or

$e\frac{1000V}{T}=6$

Also $I=e^{\frac{1000V}{T}}-1$

$\frac{dI}{dV}=\left ( \frac{1000}{T} \right ).e^{\frac{1000V}{T}}$

$\Rightarrow dI=\left ( e^{\frac{1000V}{T}} \right ).\frac{1000}{T}dV$

$\Rightarrow dI=6\times \frac{1000}{300}\times 10^{-2}$

=0.2mA

Posted by

HARSH KANKARIA

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