Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The current voltage relation of diode ise relation of diode is given by I = (e1000V/T  -1)  mA, where the applied voltage V is in volts and the temperature T is in degree Kelvi

The current voltage relation of diode ise relation of diode is given by I = (e1000V/T  -1)  mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring    V while measuring the current of 5 mA at 300 K,what will be the error in the value of current in mA ?

Option: 1

   0.2 mA


Option: 2

0.02 mA


Option: 3

0.5 mA


Option: 4

0.05 mA


Answers (1)

best_answer

Given 5 mA=\left ( e^{\frac{1000V}{T}}-1 \right )

or

e\frac{1000V}{T}=6

Also I=e^{\frac{1000V}{T}}-1

\frac{dI}{dV}=\left ( \frac{1000}{T} \right ).e^{\frac{1000V}{T}}

\Rightarrow dI=\left ( e^{\frac{1000V}{T}} \right ).\frac{1000}{T}dV

\Rightarrow dI=6\times \frac{1000}{300}\times 10^{-2}

=0.2mA

Posted by

HARSH KANKARIA

View full answer

Similar Questions

Trending Articles/News

anam-khan

BITSAT 2025 admit card out at bitsadmission.com; exam from May 26
anam-khan

BITSAT Admit Card 2025 (OUT) LIVE: BITS session 1 hall ticket at bitsadmission.com; exam from May 26, updates
anam-khan

BITSAT 2025 slot booking begins at bitsadmission.com; admit card on May 22

Latest Question