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The decay time for a nuclear process is given by \mathrm{t=8 t_{1 / 2}}. The relation b/w the mean time \mathrm{\left ( \tau \right )} and the time of decay is given by

Option: 1

\mathrm{4\, \tau \, ln2}


Option: 2

\mathrm{8\, \tau \, ln2}


Option: 3

\frac{\tau^{2} \ln 2}{4}


Option: 4

\frac{ln2}{\tau}


Answers (1)

best_answer

\mathrm{\because t_{1 / 2}=\frac{t}{8} }
\mathrm{\text { \& } \tau=\frac{1}{\lambda}=\frac{t_{1 / 2}}{\ln 2} \Rightarrow t_{1 / 2}=\tau \ln 2 }
\mathrm{\frac{t}{8}=\tau \ln 2 \Rightarrow t=8 \tau \ln 2 }

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Rishabh

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