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The diameter of the circle x^2+y^2-4 x+2 y-11=0 corresponding to a system of chords parallel to the line x-2 y+1=0

Option: 1

x-2 y+3=0


Option: 2

2 x-y+3=0


Option: 3

2 x+y-3=0


Option: 4

None of these


Answers (1)

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The centre of the given circle is (2,-1) the equation of the line perpendicular to chord x-2 y+1=0 is

2 x+y+k=0
Since the line passes through the point (2,-1) therefore k=-3. The equation of diameter is 2 x+y-3=0

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