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The diameter of the circle, whose centre lies on the line x+y=2 in the first qaudrant and which touches both the lines x=3 and y=2, is_____
Option: 1 1
Option: 2 2
Option: 3 3
Option: 4 4

Answers (1)

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The center of the circle = (k,2-k) circle is pass via point (0,2) and (3,0)

\frac{k-3}{\sqrt{1^{2}+0^{2}}}=\left | \frac{2-k-2}{\sqrt{1^{2}+0^{2}}} \right |

\left | k-3 \right |=\left | k \right |

\left | k-3 \right |=\pm k

k=\frac{3}{2}

centre =\left (\frac{3}{2} , \frac{1}{2} \right )

diameter (x) = 2\times \left | k-3 \right |=2 \times \left | \frac{3}{2}-3 \right |=2\times \frac{3}{2}=3 unit
 

Posted by

Suraj Bhandari

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