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  • The digits 1, 2, 3, 4, 5, 6, and 7 may be repeated to make how many numbers between 90 and 999?Option: 1 392<div cl

The digits 1, 2, 3, 4, 5, 6, and 7 may be repeated to make how many numbers between 90 and 999?

Option: 1

392


Option: 2

409


Option: 3

512

 


Option: 4

602


Answers (1)

best_answer

The given digits are 1, 2, 3, 4, 5, 6, and 7.

To find the numbers formed between 90 and 999.

Between 90 and 999, the numbers are 2-digit and 3-digit.

Each digit can be filled in 7 ways because repetition is allowed.

The number of the 2-digit numbers formed is given by,

7\times7=49
The number of the 3-digit numbers formed is given by,

7\times7\times=343

Thus, the total number of ways the numbers can be formed is,

49+343=392

Therefore, the number of ways is 392.

Posted by

shivangi.shekhar

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