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The dipole moments of CCl₄, CHCl₃ and CH₄ are in the order:
Option: 1 $CH_4=CCl_4<CHCl_3$
Option: 2 $CHCl_3<CH_4=CCl_4$
Option: 3 $CH_4<CCl_4<CHCl_3$
Option: 4 $CH_4<CCl_4<CHCl_3$

Answers (1)

best_answer

Let us first look at the structures of the given compounds

$\mathrm{Clearly \ \mu \neq 0 \textrm{ of CHCl}_3}$

Therefore, Option(1) is correct.

Posted by

Kuldeep Maurya

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