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  • The displacement of simple harmonic oscillator after  seconds starting from its mean position is equal to half of its amp

The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is :

Option: 1

\mathrm{6s}


Option: 2

\mathrm{8s}


Option: 3

\mathrm{12s}


Option: 4

\mathrm{36s}


Answers (1)

best_answer

\mathrm{T \rightarrow time\: period},

\mathrm{\frac{T}{12}=3 }\\

\mathrm{T=36 \text { second }}

Hence the correct answer is option 4.

Posted by

Divya Prakash Singh

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