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  • The distance between the circumcentre and orthocentre of the triangle whose vertices are ,<img alt="(6,8)" src="

The distance between the circumcentre and orthocentre of the triangle whose vertices are (0,0),(6,8) and (-4,3) is

Option: 1

\frac{125}{8}


Option: 2

\frac{\sqrt{5}}{2}


Option: 3

\frac{5 \sqrt{5}}{2}


Option: 4

5 \sqrt{5}


Answers (1)

best_answer

The given triangle is a right angled at (0,0)

\Rightarrow(0,0) is the orthocentre and mid-point of line joining (-4,3) and (6,8) is the circumcentre

Since the mid-point is \left(1, \frac{11}{2}\right) then the required distance

=\sqrt{(0-1)^{2}+\left(0-\frac{11}{2}\right)^{2}}=\frac{5 \sqrt{5}}{2}

Posted by

avinash.dongre

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