Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The distance between the circumcentre and orthocentre of the triangle whose vertices are ,<img alt="(6,8)" src="

The distance between the circumcentre and orthocentre of the triangle whose vertices are (0,0),(6,8) and (-4,3) is

Option: 1

\frac{125}{8}


Option: 2

\frac{\sqrt{5}}{2}


Option: 3

\frac{5 \sqrt{5}}{2}


Option: 4

5 \sqrt{5}


Answers (1)

best_answer

The given triangle is a right angled at (0,0)

\Rightarrow(0,0) is the orthocentre and mid-point of line joining (-4,3) and (6,8) is the circumcentre

Since the mid-point is \left(1, \frac{11}{2}\right) then the required distance

=\sqrt{(0-1)^{2}+\left(0-\frac{11}{2}\right)^{2}}=\frac{5 \sqrt{5}}{2}

Posted by

avinash.dongre

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: NIT Rourkela records higher closing ranks in CSE, ECE, AI; core engineering branches stable
anam-khan

JEE Main 2026: IIT Delhi’s CSE, EE most opted; last 2 year’s closing ranks for all categories
anam-khan

Must provide CBSE 11th registration numbers to JEE Mains aspirants, board tells schools

Latest Question