Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The distance between two points differing in phase by on a wave having wave velocity <img alt="360

The distance between two points differing in phase by 60^{\circ} on a wave having wave velocity 360 \mathrm{~m} / \mathrm{s}^{-1}and frequency 500 \mathrm{~Hz} is -
 

Option: 1

0.36 \mathrm{~m}


Option: 2

0.18 \mathrm{~m}


Option: 3

0.48 \mathrm{~m}


Option: 4

0.12 \mathrm{~m}


Answers (1)

best_answer

Use, \mathrm{\Delta \phi=\frac{2 \pi}{\lambda} \cdot \Delta x }
\begin{aligned} \mathrm{\therefore \Delta x=\frac{(\Delta \phi) \cdot \lambda}{2 \pi}} & \mathrm{=\frac{(\Delta \phi)(u / f)}{2 \pi}} \\ \mathrm{\Delta x }& =\mathrm{\frac{(\pi / 3)(360 / 500)}{2 \pi}} \\ \mathrm{\Delta x} & =\mathrm{0.12 \mathrm{~m} } \end{aligned}
 

Posted by

Kuldeep Maurya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question