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The earth's magnetic field lines resemble a dipole at the centre of the earth. If the magnetic moment of this dipole is close to  8\times 10^2^2 Am^2

, the value of earth's magnetic field (in gauss) near the equator is close to (radius of earth =6.4\times 10^6 m ) (give answer till 1 decimal place)

Option: 1

0.3

 


Option: 2

1.2


Option: 3

1.8


Option: 4

0.6


Answers (1)

best_answer

 

Given \ \ M=8 \times 10^{22} A m^{2}$\\ $d=R_{e}=6.4 \times 10^{6} m$ \\ Earth's magnetic field at equator, \\ $B=\frac{\mu_{0}}{4 \pi} \cdot \frac{M}{d^{3}}$ $=\frac{4 \pi \times 10^{-7}}{4 \pi} \times \frac{ 8 \times 10^{22}}{\left(6.4 \times 10^{6}\right)^{3}}$ $\cong 0.3 \ Gauss

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Ritika Kankaria

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