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  • The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by <img alt="\begin{aligned} & \mathrm{E}_x=\mathrm{E}_0 \sin (\mathrm{kz}-\

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by
\begin{aligned} & \mathrm{E}_x=\mathrm{E}_0 \sin (\mathrm{kz}-\omega \mathrm{t}) \\ & \mathrm{B}_y=\mathrm{B}_{\mathrm{o}} \sin (\mathrm{kz}-\omega \mathrm{t}) \end{aligned}
Then the correct relation between \mathrm{ E_o\: and\: B_o} is given by
 

Option: 1

\mathrm{E}_0 \mathrm{~B}_0=\omega k

 


Option: 2

\mathrm{E}_0=\mathrm{kB}_0
 


Option: 3

\mathrm{kE}_{\mathrm{o}}=\omega \mathrm{B}_{\mathrm{o}}
 


Option: 4

\omega \mathrm{E}_{\mathrm{o}}=\mathrm{kB}_{\mathrm{o}}


Answers (1)

best_answer

 by theory of EM wave
\frac{E_0}{B_0}=\mathrm{v}=\frac{\omega}{\mathrm{K}}

Posted by

Irshad Anwar

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