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The electric field intensity produced by a bulb at distance of 6 \mathrm{~m}\ is\ E having parer of bulb is 50 \mathrm{\omega}. The electric field intensity produced by the radiation coming from 120 \mathrm{~\omega} bulb at same distance of 6 m is given as \small \sqrt{\frac{X}{10}} E where the value of  x is:-

 

Option: 1

12


Option: 2

24


Option: 3

18


Option: 4

30


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