Get Answers to all your Questions

header-bg qa

The electric flux for Gaussian surface A that enclose the charged particles in free space is (Given \mathrm{q_1=-14\ \mathrm{nc}, q_2=78.85\ \mathrm{nc},q_3=-56\ n c})

Option: 1

\mathrm{10^3 \mathrm{Nm}^2 \mathrm{C}^{-1}}


Option: 2

\mathrm{10^3<N^{-1} \mathrm{~m}^{-2}}


Option: 3

\mathrm{6.32 \times 10^3 \mathrm{Nm}^2 \mathrm{c}^{-1}}


Option: 4

\mathrm{6.32 \times 10^3 \mathrm{cn}^{-1} \mathrm{~m}^{-2}}


Answers (1)

best_answer

\mathrm{\text { Total flux }=\frac{Q}{G_0}}
\mathrm{=\frac{-14 \times 10^{-9}+7885 \times 10^{-9}-\\ 56 \times 10^{-9}} {\epsilon _{0}}}
\mathrm{\begin{aligned} & =\frac{8.85 \times 10^{-1}}{8.85 \times 10^{-12}} \\ \phi & =10^3 \mathrm{Nm}^2 / \mathrm{c} \end{aligned}}

Posted by

Divya Prakash Singh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE