Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

The electric potential V at any point O( x, y, z all in metes) in space is given by v=4 x^{2} volt. The electric field at the point (1 \mathrm{~m}, 0,2 \mathrm{~m})  in volt/metre is-

Option: 1

8 along negative x-axes.


Option: 2

 8 along positive x -axes.


Option: 3

16 along negative x-axes.


Option: 4

16 along positive z-axes.


Answers (1)

best_answer

\text{we know that, } \vec{E}=-\frac{d v}{d r}
                               \vec{E}=-\left[\frac{d v}{d x} \hat{\imath}+\frac{d}{d y} \hat{\jmath}+\frac{d}{d z} \hat{k}\right]
                              \vec{E}=-[8 x \hat{i}+0 \hat{\jmath}+0 \hat{k}]
                               \vec{E}=-8 x \hat{i}

at point (1 \mathrm{~m}, 0,2 \mathrm{~m}) \Rightarrow \bar{E}=-16 \hat{i} Ans.

Posted by

Shailly goel

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: JCECEB invites fresh applications for Jharkhand state merit list correction

Latest Question