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  • The electric potential at the centre of two concentric half rings of radii <img alt="\mathrm{R_{1} and R_{2}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BR_%7B1%7D%20and%20R_%

The electric potential at the centre of two concentric half rings of radii \mathrm{R_{1} and R_{2}}, having same linear charge density \lambda is :

 

Option: 1

\frac{\lambda}{2 \varepsilon_0}




 


Option: 2

\frac{\lambda}{4 \varepsilon_0}


Option: 3

\frac{2 \lambda}{\varepsilon_0}


Option: 4

\frac{\lambda}{\varepsilon_0}


Answers (1)

best_answer

\begin{aligned} & \mathrm{V}_{\mathrm{C}}=\frac{\mathrm{K}}{\mathrm{R}_1} \mathrm{q}_1+\frac{\mathrm{kq}_2}{\mathrm{R}_2} \\ & =\frac{1}{4 \pi \varepsilon_0} \times \frac{\lambda \pi \mathrm{R}_1}{\mathrm{R}_1}+\frac{1}{4 \pi \varepsilon_0} \times \frac{\lambda \pi \mathrm{R}_2}{\mathrm{R}_2} \\ & =\frac{\lambda}{2 \varepsilon_0} \end{aligned}

Posted by

jitender.kumar

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