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  • The electric potential is given by as a function of distance <img alt="\mathrm{x(m)}" src="https://en

The electric potential \mathrm{V} is given by as a function of distance \mathrm{x(m)} by -
\mathrm{v=\left(5 x^{2}+10 x-9\right) \text { volt }}. value of electric field at \mathrm{x= 1} is-



 

Option: 1

20 \mathrm{~V} / \mathrm{m}


Option: 2

6 \, \mathrm{v/m}


Option: 3

11 \mathrm{v} / \mathrm{m}


Option: 4

-20 \mathrm{v} / \mathrm{m}


Answers (1)

best_answer

we know electric field is given by -

\vec{E}=-\frac{d v}{d x}=-\frac{d}{d x}\left[5 x^{2}+10 x-9\right]
\vec{E}=\left(-10 x^{2}-10\right)

Now,
         Electric field at x= 1 become
(\vec{E})_{\text {at } k=1} =-10 -10 \\
                     =-20 \, \mathrm{v} / \mathrm{m} Ans. 

Posted by

shivangi.bhatnagar

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