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The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm is incident on it. The band gap (in eV) for the semiconductor is

Option: 1

0.9


Option: 2

0.7


Option: 3

0.5


Option: 4

1.1


Answers (1)

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\mathrm{\text { Band gap, } \mathrm{E}_{\mathrm{g}}=\frac{\mathrm{hc}}{\lambda}=\frac{\left(6.6 \times 10^{-34}\right)\left(3 \times 10^8\right)}{2480 \times 10^{-9} \times 1.6 \times 10^{-19}} \mathrm{eV}=0.49 \mathrm{eV}}

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