Browse by Stream
QnA
Home

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The energies E1 and E2 of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths i.e <img alt="\lambda _{1}" src="https://learn.careers360.com

The energies E1 and E2 of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths i.e \lambda _{1} and \lambda _{2} will be:

Option: 1

\lambda _{1}=\lambda _{2}


Option: 2

\lambda _{1}=2\lambda _{2}


Option: 3

\lambda _{1}=4\lambda _{2}


Option: 4

\lambda _{1}=\frac{1}{2}\lambda _{2}


Answers (1)

We know that,

\\E_{1} = \frac{hc}{\lambda _{1}} \\ \\ E_{2} =\frac{hc}{\lambda _{2}}\\ \\ \frac{E_{1}}{E_{2}} = \frac{\lambda _{2}}{\lambda _{1}}\\ \\ \frac{1}{2} = \frac{\lambda _{2}}{\lambda _{1}}\\ \\ \lambda _{1} = 2\lambda _{2}

Hence, the option number (2) is correct.

Posted by

Kshitij

View full answer

Similar Questions

Latest Question