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The energy density associated with electric field E and magnetic field B of an electromagnetic wave in free space is given by

( $\varepsilon_0$ - permittivityof freespace , $\mu_0$ - permeability of free space)

Option: 1
$\mathrm{U}_{\mathrm{E}}=\frac{\epsilon_0 \mathrm{E}^2}{2}, \mathrm{U}_{\mathrm{B}}=\frac{\mathrm{B}^2}{2 \mu_0}$

Option: 2
$\mathrm{U}_{\mathrm{E}}=\frac{\mathrm{E}^2}{2 \epsilon_0}, \mathrm{U}_{\mathrm{B}}=\frac{\mu_0 \mathrm{~B}^2}{2}$

Option: 3
$\mathrm{U}_{\mathrm{E}}=\frac{\mathrm{E}^2}{2 \epsilon_0}, \mathrm{U}_{\mathrm{B}}=\frac{\mathrm{B}^2}{2 \mu_0}$

Option: 4
$\mathrm{U}_{\mathrm{E}}=\frac{\epsilon_0 \mathrm{E}^2}{2}, \mathrm{U}_{\mathrm{B}}=\frac{\mu_0 \mathrm{~B}^2}{2}$

Answers (1)

best_answer

By theory of electromagnetic waves

$\mathrm{U}_{\mathrm{E}}=\frac{1}{2} \varepsilon_0 \mathrm{E}^2$ and

$\mathrm{U}_{\mathrm{B}}=\frac{1}{2} \frac{\mathrm{B}^2}{\mu_0}$

Posted by

Gautam harsolia

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