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The equation of a circle of radius 1 touching the circles \mathrm{x^{2}+y^{2}-2|x|=0} is

Option: 1

\mathrm{x^{2}+y^{2}+2 \sqrt{3} x-2=0}


Option: 2

\mathrm{x^{2}+y^{2}-2 \sqrt{3} y+2=0}


Option: 3

\mathrm{x^{2}+y^{2}+2 \sqrt{3} y+2=0}


Option: 4

\mathrm{x^{2}+y^{2}+2 \sqrt{3} y+2=0}


Answers (1)

best_answer

The given circles are \mathrm{x^{2}+y^{2}-2 x=0, x>0\: and \: x^{2}+y^{2}+2 x=0, x<0} From the figure the centre of the required circle will be \mathrm{(0, \sqrt{3})\: and \: (0,-\sqrt{3})}.

Hence (B) is the correct answer.

 

Posted by

Gautam harsolia

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