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The equation of a line passing through the centre of a rectangular hyperbola is  \mathrm{x-y-1=0}.  if one of its asymptote is \mathrm{3x-4y-6=0}, then equation of its other asymptote is

Option: 1

\mathrm{4 x+3 y+17=0}


Option: 2

\mathrm{4 x+3 y-17=0}


Option: 3

\mathrm{4 x+3 y-15=0}


Option: 4

\mathrm{4x+3y+15=0}


Answers (1)

best_answer

Pt of intersection of \mathrm{x-y-1=0} and \mathrm{3x-4y-6=0} is (-2,-3) other asymptote will be in the form of \mathrm{4x+5y+\lambda=0}   and it should pass through  (-2,-3) . Thus \mathrm{\lambda=-17}

Posted by

Devendra Khairwa

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