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  • The equation of a line passing through the centre of a rectangular hyperbola is . If one

The equation of a line passing through the centre of a rectangular hyperbola is \mathrm{x-y-1=0}. If one of its asymptotes is \mathrm{3 x-4 y-6=0}, the equation of the other asymptote is

Option: 1

\mathrm{4 x-3 y+17=0}


Option: 2

\mathrm{-4 x-3 y+17=0}


Option: 3

\mathrm{-4 x+3 y+1=0}


Option: 4

\mathrm{4 x+3 y+17=0}


Answers (1)

best_answer

The centre is the point of intersection of the given lines

i.e. (-2,-3)so the other asymptote passing through (-2,-3)

and perpendicular to the first asymptote will be 4(\mathrm{x}+2)+3(\mathrm{y}+3)=0.

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