Get Answers to all your Questions

header-bg qa

The equation of a stationary wave is- \mathrm{ y=0.8 \cos \left(\frac{\pi x}{20}\right) \sin 200 \pi t \text {, where } x } is in \mathrm{ \mathrm{cm} \: \: and\: \: t } is in second. The separation between consecutive nodes will be-
 

Option: 1

20 \mathrm{~cm}
 


Option: 2

10 \mathrm{~cm}
 


Option: 3

40 \mathrm{~cm}
 


Option: 4

30 \mathrm{~cm}


Answers (1)

best_answer

\mathrm{\frac{2 \pi}{\lambda}=\frac{\pi}{20} \Rightarrow \lambda=40 \mathrm{~cm}}

separation Between two consecutive nodes.

\mathrm{ =\frac{\lambda}{2}=\frac{40}{2}=20 \mathrm{~cm} \text {. } }

Hence option 1 is correct.

 

Posted by

mansi

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE