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The equation of a straight line equally inclined to the axes and equidistant

from the points (1.-2) and (3,4) is 

Option: 1

\mathrm{x+y+1=0}


Option: 2

\mathrm{x+y+2=0}


Option: 3

\mathrm{x-y-2=0}


Option: 4

\mathrm{x-y-1=0}


Answers (1)

best_answer

Middle point of the line joining points (1,-2) and (3,4) is (2,1) which lie on

line  \mathrm{x-y-1=0}  , which is equally inclined to the axes and is at equal distance

from the given points.

Hence correct answer is (d).

Posted by

SANGALDEEP SINGH

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